Maybe the old saying of “tough times don’t last, tough people do” applies to the folks in Parachute and Battlement Mesa schools. They’re certainly going through some tough times since the Great ...
Post Independent Citizen Telegram: McKibbin’s Scribblin’s: Tough times, good people, hard decisions
Bonus 2: repeating a 2D array this way takes a little bit more work, converting to rows a few times before wrapping back to the desired dimensions. You can of course use LET to keep things tidy if you don't want to define the array twice:
I am getting × in alert. I need to get × as result. Anybody knows or faces this problem? Please update your suggestions.
How do i calculate the probability of a result happening X amount of times in a row? Imagine an event with 6 possible outcomes. 1st outcome has chance of 40%, 2nd has a chance of 20%, 3rd 15%, 4th 10%, 5th 10%, 6th 5%.
Calculating the odds of a specific outcome happening X amount of times ...
"Infinity times zero" or "zero times infinity" is a "battle of two giants". Zero is so small that it makes everyone vanish, but infinite is so huge that it makes everyone infinite after multiplication. In particular, infinity is the same thing as "1 over 0", so "zero times infinity" is the same thing as "zero over zero", which is an indeterminate form. Your title says something else than ...
The solution is to restore the table N times by using UNDROP; and it only works if there is no table with the same name. N is a number of times the table is recreated using CREATE OR REPLACE; and time travel doesn't work as CREATE OR REPLACE drops the table and recreates it. I have created a table with some dummy data to test it.