Lewis Structure Of Hno

I started with the solution by deciding the Lewis acid out of $\ce {HNO_3}$ and $\ce {HNO_2}$. I guess $\ce {HNO_3}$ should be Lewis acid as O.S. of N is higher in it. Hence, I wrote the reaction to generate electrophile: $$\ce {HNO_3 + HNO_2 -> NO_3^- + H_2O + NO^+}$$ Now, it is a bit clear who's the electrophile. Hence, I thought that first option would be the final product. But, according ...

Certainly, the nitrogen of HNO 3 fits the bill where M = NO 2 in structure 2. In this instance, nitrogen is n = 5 in structure 2 and 4. Bear in mind that for the purpose of electronic bookkeeping, transformation of the acyl anion 5 to a acyl cation 2 is a 2-electron oxidation while species M undergoes a 2-electron reduction. --- continued ---

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Lewis Structure Of Hno 3

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Lewis Structure Of Hno 5

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Lewis Structure Of Hno 8