Answer: HCF of 408 and 1032 is 24. Explanation: The HCF of two non-zero integers, x (408) and y (1032), is the highest positive integer m (24) that divides both x (408) and y (1032) without any remainder. Let's look at the different methods for finding the HCF of 408 and 1032.
HCF of 408 and 1032 | How to Find HCF of 408, 1032? - Cuemath
The steps used to find the HCF of 408 and 1032 using different methods are provided in this article for a good hold on the concepts. The HCF of 408 and 1032 is 24, divides 408 and 1032 evenly.
Therefore, the HCF of the numbers 408 and 1032 is 24. It is given that the HCF is in the form of 1032 m 408 × 5. Now we will equate this form to 24 to get the value of m. Therefore, we get. Hence, the value of m is 2.
If the HCF of 408 and 1032 is expressible in the form - Vedantu
To solve the problem, we need to find the HCF (Highest Common Factor) of the numbers 408 and 1032, and then express it in the form given in the question. Here’s a step-by-step solution: ### Step 1: Find the HCF of 408 and 1032 using the Euclidean algorithm.
If the HCF of 408 and 1032 is expressible in the form `1032\ m-408xx5 ...
If the Hcf of 408 and 1032 is Expressible in the Form 1032 M − 408 × 5 ...
To determine the HCF (Highest Common Factor) of 408 and 1032, we will use the prime factorization method. The common prime factors are 2 and 3. HCF = 2^3 × 3^1 = 24. The problem states that the HCF can be expressed as 1032m - 408 × 5. m = 2. Given the representation of the HCF in the equation, the value of m is 2.